Comments on: GLAT #16 http://divinelunacy.com/2004/10/glat-16/ Coffee... Sat, 11 Oct 2008 02:21:18 +0000 http://wordpress.org/?v=2.2.3 By: Greggy http://divinelunacy.com/2004/10/glat-16/#comment-981 Greggy Wed, 15 Jun 2005 16:00:55 +0000 http://divinelunacy.com/2004/10/glat-16/#comment-981 In the case that it is not a right, you would use the isoperemetirc point of the triagle. The isoperemetric point is the center of both soddy cirlces. The outer soddy circle is tangent to three tangent circles drawn about each of the points. In the case that it is not a right, you would use the isoperemetirc point of the triagle. The isoperemetric point is the center of both soddy cirlces. The outer soddy circle is tangent to three tangent circles drawn about each of the points.

]]> By: Randall Munroe http://divinelunacy.com/2004/10/glat-16/#comment-977 Randall Munroe Tue, 14 Jun 2005 20:57:12 +0000 http://divinelunacy.com/2004/10/glat-16/#comment-977 But what if it's NOT a right triangle like that? The solution still exists, but how can you be sure your method works? (I think it does; that looks like the one I stumbled on. But have you considered it?) But what if it’s NOT a right triangle like that? The solution still exists, but how can you be sure your method works?

(I think it does; that looks like the one I stumbled on. But have you considered it?)

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